About this calculator
In AC circuits, the power that does useful work (kW) is less than voltage × current (kVA) when the power factor is below 1, as it is for motors and other inductive loads. This calculator gives real, apparent and reactive power, or the current a load will draw — for both single-phase and balanced three-phase supplies.
Formula
Three-phase: P = √3 × VL × I × cos φ S = √3 × VL × I
Single-phase: P = V × I × cos φ S = V × I
Q = √(S² − P²)
P = real power (W), S = apparent power (VA), Q = reactive power (VAR), VL = line-to-line voltage, cos φ = power factor.
Worked example
- Three-phase, 400 V, 10 A, PF 0.8: P = 1.732 × 400 × 10 × 0.8 = 5.54 kW; S = 6.93 kVA; Q = 4.16 kVAR.
- Current for a 15 kW three-phase load at 400 V, PF 0.85: I = 15 000 ÷ (1.732 × 400 × 0.85) = 25.5 A.
- Single-phase 230 V, 10 A, PF 1: 2.3 kW.
Assumptions and limitations
- Three-phase results assume a balanced load (equal current in each line) and sinusoidal voltage and current.
- For a motor, the kW entered or calculated is electrical input power. Motor nameplate kW is output power — divide by the motor efficiency to get input power.
- Harmonics from drives and electronic loads are not included.
Safety note
This calculator does not size cables, breakers or protection. Electrical installations must be designed and installed by qualified persons according to your local wiring regulations.
References
- Standard AC power relations for single-phase and balanced three-phase systems (IEC 60050 definitions of active, reactive and apparent power).
